Solve the following equations

Question

1. x^2/3=36
2. (x+2)^3/2=27
3. 3x^4/3-8=40
4. (x-5)^1/3=3

Answer 1

 Alternate solution for #3 if the parenthesis are in a different location

3x^4/3-8=40 Add 8 to both sides

3x^4/3-8+8=40+8 Simplify

3x^4/3=48 Divide both sides by 3

3x^4/3/3=48/3 Simplify

x^4/3=16 Raise both sides the the 3/4

(x^4/3)^3/4=(16)^3/4

x=8

Answer 2

1. x^2/3=36

(x^2/3)^3/2 = 36^3/2

x= 216

2. (x+2)^3/2=27

((x+2)^3/2)^2/3 = 27^2/3

x+2 = 9

x = 7

3.its not very clear if you wrote the equation in the right form. Make sure you use parentheses to write the equation in the proper form

3x^4/3-8=40

3x^4/3-8 = 40

3x^20/3 = 40

x^20/3 = 40/3

(x^20/3)^3/20 = (40/3)^3/20

x = (40/3)^3/20

4.(x-5)^1/3=3

(x-5)^1/3 = 3

((x-5)^1/3)³ = 3³

x-5 = 27

x = 27+5

x= 32