
Martin S. answered 04/27/20
Patient, Relaxed PhD Molecular Biologist for Science and Math Tutoring
To find the equation of a linear equation given two points you need to first use the coordinates to find the slope of the line, and then use the pouint slope formulat to get the equation.
First, let's get the slope. That would be the change of y divided by the change of x, or the rise divided by the run. We have two points to work with, (3,2) and ((6,10), which are (x1, y1) and (x2, y2). Subtratct y1 from y2 to get the change of y, or the rise:
10 - 2 = 8
Then subtract x1 from x2 to get the change of x, or the run:
6 - 3 = 3
Now divide the change of y by the change of x:
8/3 = slope
Now we can choose either of the points to plug into the point/slope formule,
(y - y1) = m(x - x1), remember that m is equal to the slope of the line, so let's use the point (3,2)
(y - 2) = 8/3(x - 3), distribute the 8/3 across (x - 3)
(y - 2) = (8/3)x - 8, add 2 to both sides
y = (8/3)x -6, or y = 8x/3 - 6
For the second question, we will use the relationship that for an exponential function y = abx, and then plug in the x and y values from the two data points. Let's work that out:
For (3,2), we get
2 = ab3
And for (6,10) we get
10 = ab6
Now divide the second equation by the first one, and we have:
(10 = ab6 )/(2 = ab3 ) = (5 = b3)
So b = 51/3
Now substitute that value for b into either equation to get a
The first equation will be easier because (b3)1/3 = b, so we get
2 = ab3 , plug in 51/3 for b, so that is
2 = a (51/3)3 = 5a, so a = 2/5
Now we have a and b, so plug those into y = a(bx), and we get
y = 2/5(51/3)x , and then simplifying using the multiplication rule of exponents, we get
y = 2/5(5x/3)
Hope this helps