
Tim T. answered 05/09/20
Math: K-12th grade to Advanced Calc, Ring Theory, Cryptography
Greetings! Lets solve this shall we ?
So, we must find what (a-b) is given the function f(x) = ax2 + bx + c, with f(0) = 1 and f(-1) = 3. First, lets begin with f(0) = 1 such that
f(0) = a(0)2 + b(0) + c = 1. Then c = 1 ! Then we find f(-1) = a(-1)2 + b(-1) + c = 3. Next, we see that
f(-1) = a - b + c = 3.......We plug in c = 1 to get
a - b + 1 = 3........Finally, subtract 1 to get
(a - b) = 2 !
I hope this helped!