J.R. S. answered 04/26/20
Ph.D. in Biochemistry--University Professor--Chemistry Tutor
Comparing experiment 3 to 2, [CO] is doubled from 0.25 to 0.50 while [Cl2] remains constant at 0.80. The rate goes from 1.97 to 3.94, i.e. it doubles. This tells us that the reaction is 1st order in CO. Next, we compare experiment 1 to 3 where [CO] is constant and [Cl2] is doubled from 0.40 to 0.80. The rate goes from 0.606 to 1.97, i.e. it increases 2.8 fold (almost 3 fold). This would equate to a 1.6 order (less than 2nd order and greater than 1st order)
rate = k[CO][Cl2]1.6
0.696 M/s = k [0.25 M][0.40 M]1.6
0.696 M/s = 0.0677 k
k = 10.3 M-1.6s-1
NOTE: This is a strange question since usually they give you even numbers for the order of the reaction. The observation that the order is 1.6 with respect to Cl2 makes me think there may be an error in the data.