world problem

Question

Hexane has a density of 0.659g/mL. How many milliliters(mL) would you need to pour in order to get 49.5 g of hexane.

Answer 1

This is a ratio problem. We would write it as follows:

 

(.659g)/1mL = (49.5g)/(x mL)

 

We then solve for x.

 

Since x is on the denominator, we multiply both sides by x to get

 

.659x = 49.5

 

We want to get x by itself, so now we multiply both side by .659 to get 

 

x = 49.5/.659 which is 75.113

Answer 2

Density x volume = mass

 

So .659 g/ml * V = 49.5 g

 

V = 49.5 / .659 = 75.11 mL