find all horizontal and vertical Asymptotes

Question

f(x)= (arctanx)-1/x-1

Answer 1

If it's f(x) = arctan(x) - 1/(x-1)

Then it has horizontal asymptotes at pi/2 and -pi/2, the range of arctan(x)

It has a vertical asymptote where the denominator of -1/(x-1) is undefined, which is where x-1 = 0

x=1