The "1+3" is ambiguous. Is the original problem as written below?
2x / (x2 + 2x + 1) + 3 = 7 / (x+1)
Strictly speaking,
2x/x2+2x+ 1+3= 7/x+1 should be written as (2x/x2) + 2x + 1 + 3 = (7/x) + 1 since no parentheses are used.
Let's solve the first assumed equation.
If so, the the 3 needs a common denominator on the left.
Once that is done you can combine the left, then cross multiple and solve for the values of x.
2x / (x2 + 2x + 1) + 3 =
[2x / (x2 + 2x + 1)] + [3 (x2 + 2x + 1) / (x2 + 2x + 1) ] =
[2x / (x2 + 2x + 1)] + [ (3x2 + 6x + 3) / (x2 + 2x + 1) ] =
[2x / (x2 + 2x + 1)] + [ (3x2 + 6x + 3) / (x2 + 2x + 1) ] =
(3x2 + 8x + 3) / (x2 + 2x + 1)
In hind sight, I should have subtracted 3 from both sides first.
(3x2 + 8x + 3) / (x2 + 2x + 1) = 7 / (x+1)
then cross multiple to get
(3x2 + 8x + 3) (x+1) = 7 (x2 + 2x + 1)
(3x2 + 8x + 3) (x+1) = 7x2 + 14x + 7
(3x3 + 8x2 + 3x) + (3x2 + 8x + 3) = 7x2 + 14x + 7
3x3 + 11x2 + 11x + 3 = 7x2 + 14x + 7
3x3 + 4x2 - 3x - 4 = 0
Solve for this equation. It wil have up to 3 unique roots/solutions.
Graphing this function shows three roots: x = -1, 1, and -1.33 or (-4/3)