Mark M. answered 02/03/15
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Retired Math prof with teaching and tutoring experience in trig.
Let x = speed of plane in still air
y = speed of wind
Distance = (rate)(time)
Speed against wind = x - y, so 4.5(x - y) = 2160
Speed with the wind = x + y, so, 4.5(x + y) = 2520
Divide both equations by 4.5 to get: x - y = 480
x + y = 560
Adding the equations we have 2x = 1040
x = 520 and y = 560 - x = 40
The speed of the plane in still air is 520 mph and the speed of the wind is 40 mph.