
Ken P. answered 04/17/20
Mathematics tutor with over 7 years of experience
Suppose C is Charles' age now and D is David's age now.
First, let's come up with an equation for 8 years ago.
Eight years ago Charles was 1 year older than twice David's age then.
C - 8 = 2(D - 8) + 1
We subtract 8 for both C and D since this is about 8 years ago.
Next, let's come up with an equation for 8 years from today.
In eight years, Charles will be 7/6 as old as David will be then.
C + 8 = (7/6) · (D + 8)
Similar to the previous, we add 8 to both C and D since this is about 8 years from now.
Since we have 2 variables and 2 equations, it is solvable by either substitution or elimination.
This is your choice of preference.
*Please feel free to ask me any question for clarification.