Richard B. answered 04/17/20
All levels of algebra was required for my physics and EE degree
I agree with your answers. In the first case you set up the growth equation to be equal to the final value equals the initial value times e raised to the KT power, where T at this point is in days. So the first goal is to determine what decay is. So I set 3000 equals 1200 (e)^k2. Solving for K, I got K = .458. Now let's determine a final value (call it F) after seven days (five additional days to the first calculation of 2 days). Using the K from above, I got: F equals, 29,616.
For your second problem I took the number of permutations of five things taken one at a time, and I got 5. In fact in this case it doesn't matter if you take the number of combinations or permutations. Then you have this raised the ninth power for nine different questions with five optional answers. Five to the ninth is equal to 1,953,125. This is so big that for each of the nine questions only one of the five options can be chosen as the possible correct answer