ALGEBRA PROBLEM! PLEASE HELP! I NEED TO MAKE SURE IT’S CORRECT!

Question

a

——————

b²a — 2a

———

b + 1

—

b

(A) (1)/(b²-2ab³)

(B) (b(1+b))/(-2 + b³ + b⁴)

(C) (1 + b²)/(-2b + b² + b⁴)

(D) (b² + 1)/(b³-2b)

(E) None of the above

For this I got; (C). Is this correct?

Answer 1

Assuming the compound fraction

(a / (b²a - 2a)) / ((b + 1) / b)

(1 / (b² - 2))(b / (b + 1)

b / (b³ + b² - 2b - 2)

Answer 2

denomaintor:

b^2a - 2a/ (b + 1/b) =

b^2 - 2a / (b^2+1)/b =

b^2 - 2ab/(b^2+1) =

[b^2 (b^2+1) - 2ab ]/(b^2+1) =

[b^4 + b^2 - 2ab]/(b^2+1) =

the reciprocal of this gets multiplied by a:

a(b^2+1) / [b^4 + b^2 - 2ab]

It is none of the above