Inactive Tutor answered 05/29/20
Tutor
New to Wyzant
y = a(x - h)2 + k
h = 2
k = 5
y = a(x - 2)2 + 5
0 = a(-3 - 2)2 + 5
0 = 25a + 5
a = -1/5
y = (-1/5)(x - 2)2 + 5
Liz S.
asked 04/13/20A quadratic function has zero (x-intercept) at -3 and a vertex of (2,5). What's the equation in vertex form
Inactive Tutor answered 05/29/20
y = a(x - h)2 + k
h = 2
k = 5
y = a(x - 2)2 + 5
0 = a(-3 - 2)2 + 5
0 = 25a + 5
a = -1/5
y = (-1/5)(x - 2)2 + 5
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