A rectangular brochure is designed so that it has an area of 45 square inches and a perimeter of 27 inches. Find the width and height of the brochure. Assume the height is greater than the width.

Answer 1

A=lw

45=lw

45/w=l

P=2l+2w

27=2l+2w

13.5=l+w

13.5-w=l

l=45/w from above

set them equal to each other

45/w=13.5-w

45=13.5w-w^2

w^2-13.5w+45=0

use the quadratic equation or factor the polynomial

it's probably easier for you to use the quadratic equation but I'm going to favtor

(w-7.5)(w-6)=0

w-7.5=0

w=7.5

w-6=0

w=6

The height is 7.5 inches.

The width is 6 inches.

If you round off you will not have accurate dimensions.