Dividing Rational Expressions

Question

Multiply the following expressions. Use the   button to enter your full answer.

Answer 1

(x^2-9x+20)/(3x^2-12x)*3/(x^2+x-30)=

(3x^2-27x+60)/(3x^4+3x^3-90x^2-12x^3-12x^2+360x)=

(3(x^2-9x+20))/(3x(x^3+x^2-30x-4x^2-4x+120))=

((x-5)(x-4))/(x^3-3x^2-4x+120)=

" " /((x(x^2-3x-4))+120)=

" " /((x^2(x-3))-(4(x+30))=

That's the best I can do. I wanted to cancel something within the ( ).

Answer 2

Hi Salomon! Before we start multiplying this expression, simply factor out each term.

x^2 - 9x + 20 = (x - 4) * (x - 5)

3x^2 - 12x = 3x * (x - 4)

x^2 + x - 30 = (x - 5) * (x + 6)

Using the factored forms into the equation, you can cancel many parts, including the (x - 4),(x - 5), and 3.

⇒ 1 / ( (x)(x + 6) ) >>>>>>>>>>>>> (ANSWER)