Mark M. answered 04/11/20
Mathematics Teacher - NCLB Highly Qualified
d = Avk
150 = (44.7)(70)k
150 = 3129k
0.0479 ≈ k
419 = (37.9)v(0.0479)
Can you calculate for v and answer?
Elizabeth H.
asked 04/11/20Atmospheric drag varies jointly as an object's surface area A and its velocity v. If a car travelling at a velocity of
7070
mph with a surface area of
44.744.7
ftsquared2
experiences a drag of
150150
N, how fast must a car with
37.937.9
ftsquared2
of surface area go to experience
419419
N of drag?
Mark M. answered 04/11/20
Mathematics Teacher - NCLB Highly Qualified
d = Avk
150 = (44.7)(70)k
150 = 3129k
0.0479 ≈ k
419 = (37.9)v(0.0479)
Can you calculate for v and answer?
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