Patrick B. answered 04/10/20
Math and computer tutor/teacher
First you need parenthesis around the denominator:
(4x^2)/(x-3) - (x-1)/(x^2-9) =
(4x^2)/(x-3) - (x-1)/[(x+3)(x-3)] = <--- factors
the missing factor is (x+3)/(x+3) in the first term:
(4x^2)(x+3) / (x^2-9) - (x+1)/(x^2-9) =
[(4x^2)(x+3) - (x+1)] / (x^2-9) =
[ 4x^3 + 12x^2 - x - 1]/(x^2 - 9)