n=3 4 and 5i are zeros; f(1)=-234

Answer 1

P(x) = k(x-4)(x - 5i)(x+5i)

= k(x-4)(x^2 + 25)

P(1) = -234

-234 = k(-3)(26)

-234/-78 = k

k = 234/78 = 3

f(x) = P(x) = 3(x-4)(x^2+25)