Michelle F.

asked • 02/02/15

How fast did each hiker walk if they meet in 2 hours?

Two hikers start from the same point and hike in opposite directions around a lake whose shoreline is 13 miles long. One hiker walks 0.5 mph faster than the other hiker. How fast did each hiker walk if they meet in 2 hours?  How do I set up this equation?

1 Expert Answer

By:

Michelle F.

Can this be explained a little further please?
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02/02/15

Arthur D.

tutor
We don't know either hiker's rate so we represent them as r and r+0.5.
The distance hiker 1 walks plus the distance hiker 2 walks together total 13 miles. Also they both walk for 2 hours until they meet.
So it's d=r1t+r2t because distance=rate*time.
d=13 miles
r is 1st hiker's rate (r1)
r+0.5 is 2nd hiker's rate (r2)
t=2 hours for both hikers
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02/03/15

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