Patrick B. answered • 04/01/20
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Lw = 35
L+w = 12
L(12-l) = 35
12L - L^2 = 35
L^2 - 12L + 35 = 0
( L - 7 )( L - 5 ) = 0
rectangle 7 by 5
Joe R.
asked • 03/31/20college algebra question
Find The length and width of a rectangle whose perimeter is 24 feet and whose area is 35 ft.
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