
Patrick B. answered 03/31/20
Math and computer tutor/teacher
p = 6/30 = 1/5 = 0.2
q = 1-p = 0.8
(a) Binomial p=0.2, n=5, k=3
(5 choose 3) (0.2)^3 ( 0.8)^2 = 10 * 0.008 * 0.64 = 0.0512
(b) Binomial p=0.2, n-5 , k=0,1 -
(5 choose 1)(0.2)^1 ( 0.8)^4 = 5 * 0.2 * .4096 = 0.4096
(5 choose 0)(0.2)^0((0.8)^5 = 0,32768
total is 0.73728