x^{2 }- 2x + 20 = 0 is how we begin.

a = 1, b = -2, c = 20

x = (- b ± sqrt(b^{2} - 4ac)) / (2a)

substituting in the values we get

x= 2 ± __√( (-2)__^{2 }__– 4(1)(20))__

2(1)

work out what is under the radical and you get -76. This means the roots will be imaginary. The square root of -76 simplifies to 2 i √19

so that's __2 ± 2 i √19__

2

factor out a 2 and you get TWO complex roots

1 - i √19 and 1 + i √19

Hope this helps.