Using the quadratic formula to solve x2 + 20 = 2x, what are the values of x?

Answer 1

x² - 2x + 20 = 0 is how we begin.

a = 1, b = -2, c = 20

x = (- b ± sqrt(b² - 4ac)) / (2a)

substituting in the values we get

x= 2 ± √( (-2)² – 4(1)(20))

2(1)

work out what is under the radical and you get -76. This means the roots will be imaginary. The square root of -76 simplifies to 2 i √19

so that's 2 ± 2 i √19

2

factor out a 2 and you get TWO complex roots

1 - i √19 and 1 + i √19

Hope this helps.

Answer 2

Hi there! This problem requires you to know the quadratic formula or x= (-b±√b^2-4ac) / 2a. There is also a catchy song to memorize this formula, which I will link right here: https://www.youtube.com/watch?v=VOXYMRcWbF8.

The first step to solve this problem is to move the 2x to the other side, resulting in this equation: x^2-2x+20=0. From this you can use the quadratic equation where A=1, B=-2, and C=20. After this, you can plug in a, b, and c of the quadratic equation and you will end with x=1±i√19. The "i" in this case represents the square root of -1.

I hope this helps! Let me know if you need any other information.