
Patrick B. answered 03/09/20
Math and computer tutor/teacher
65 = t*R
185 = t*(R+40) = rt + 40t
185 = 65 + 40t
120 = 40t
t=3
65 = 3*R
R = 65/3 = 21 and 2/3
bicycle speed is 21 and 2/3
drive speed = 61 and 2/3
Jordan M.
asked 03/09/20Tammy can bicycle 65 mi in the same time it takes her to drive 185 mi. If her driving rate is 40 mi/h faster than her rate on the bicycle, find each rate.
Patrick B. answered 03/09/20
Math and computer tutor/teacher
65 = t*R
185 = t*(R+40) = rt + 40t
185 = 65 + 40t
120 = 40t
t=3
65 = 3*R
R = 65/3 = 21 and 2/3
bicycle speed is 21 and 2/3
drive speed = 61 and 2/3
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