Patrick B. answered 03/05/20
Tutor
4.7
(31)
Math and computer tutor/teacher
f(x) = k(x+3)^3
36 = k(3+3)^3
36 = k(3)^3
36 = k(27)
k = 36/27 = 4/3
f(x) = (4/3)(x+3)^3
Jocelyn R.
asked 03/05/20Zero of -3 having multiplicity 3; f(3)=36
Patrick B. answered 03/05/20
Math and computer tutor/teacher
f(x) = k(x+3)^3
36 = k(3+3)^3
36 = k(3)^3
36 = k(27)
k = 36/27 = 4/3
f(x) = (4/3)(x+3)^3
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