Algebra Problem! Please Help!

Question

0.3 x 10⁴ liters of a ideal gas under a pressure of 0.0006 x 10⁶ atmospheres had a temperature of 3500 x 10⁷ K. After the volume was doubled and the pressure increased to 0.03 x 10⁵ atmospheres, what was the temperature of this ideal gas?

(A) 3.5x10⁹

(B) 3.5x10⁸

(C) 3.5x10¹¹

(D) 3.5x10¹²

(E) None of these

Answer 1

Put the data into standard scientific notation:

V₁ = 3 x 10³

P₁ = 6 x 10²

T₁ = 3.5 x 10³

V₂ = 6 x 10³

P₂ = 3.x 10³

T₂ = x

T₁ / (P₁V₁) = T₂ / (P₂V₂)

(3.5 x 10³) / (6 x 10²)(3 x 10³) = x / (3 x 10³)(6 x 10³)

(3.5 x 10³) / (18 x 10⁵) = x / (18 x 10⁶)

(3.5 x 10³)(18 x 10⁶) / (18 x 10⁵) = x

(3.5 x 10³)(1 x 10) = x

3.5 x 10⁴