which choice is equivalent to the expression below when y is greater than or equal to 0? square root y^3+square root 9y^3-3ysquare root y

Answer 1

I'm assuming the problem is this:

Since you didn't list the "expressions below" I'll take a shot in the dark here.

First, working with the 1st expression, split the y³ up into 2 pieces, y² and y, because y²•y = y³. Then do the same to the 2nd expression only also write the 9 as 3². Like this:

√(y²•y) + √(3²•y²•y) - 3y√y

Now, take the square root of the things that are squared. The square root of y² is "y". The square root of 3² is 3. Like this:

y√y + 3y√y - 3y√y

Then, since there are two identical expressions being subtracted, the result is just y√ y

Answer 2

This is what I read from your request?

√y^{3 +} √(9y³) - 3y²√y = y√y + 3y√y - 3y²√y = y√y (4 - 3y)

And I don't see any expression below to answer your question.