Using the quadratic equation in standard form, graph the quadratic function, label the vertex and line of symmetry. y = -x^2 -6x + 11

Answer 1

 y = -x^2 -6x + 11

This is already the standard form for a quadratic....

Start by finding the roots....set the equation equal to zero, factor, and solve for x:

 -x^2 -6x + 11 = 0

 x^2 +6x - 11 = 0

Factors: (x+ 5)(x - 6)

x = -5, +6

The axis of symmetry is halfway between these points, at x = -1/2. to get the vertex, plug this into the equation and solve for y.