Andrew K. answered 01/30/15
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Hi Jennifer,
Since we know that this is an (approximately) linear relationship, we should identify our "x" and "y" parameters. In this case, I think it would be easiest to say that "x" refers to the year, and "y" refers to revenue. We can then turn the information into data points on a graph:
When the year "x" was 1990, the revenue "y" was $19.0 billion
When the year "x" was 2100, the revenue "y" was $6.0 billion
In other words, two (x,y) points on the graph are (1990,19) and (2100,6) (disregarding the "billion" on the y value - we'll just have to remember to put that back on any "y" answer we come up with)
The equation of a line (the relationship between "x" and "y") can be expressed a few different ways, usually either the slope-intercept form (y=mx+b), where we have to know the slope and the y-intercept, or the point-slope form ((y-y1)=m(x-x1)), where we have to know the slope and any point on the line. Unless we happen to know the y-intercept, I prefer to use the point-slope format. In either case, we need to know the slope of the line
Slope = Δy/Δx = rise/run = (6 - 19)/(2100 - 1990) = -13/110
We can now pick either of the points that we know to complete the (x1,y1) for the point-slope form of the equation of the line - I'll use (2100,6):
(y-6) = -13/110*(x-2100)
Now, we can use algebra to transform this into the slope-intercept form:
(y-6) = -13/110*(x-2100)
y-6 = (-13/110)*x + 27300/110
y = (-13/110)*x + 27300/110 + 660/110
y = (-13/110)*x + 27960/110
Since we want to know the revenue "y" when the year "x" is 2013, we plug in 2013 for x:
y = (-13/110)*(2013) + 27960/110
y = 16.3 (rounded to three digits)
So for a linear relationship, in 2013, the revenue would be $16.3 billion
I hope this helps!
Andy