How to find (h/g)(4)

Question

h(x)=4x^2-5

g(x)=5x-6

a. (h/g)(4)

b. Find all values that are not in the domain of h/g.

Answer 1

Hi,

h(x)=4x^2-5

g(x)=5x-6

 (h/g)(x) = h(x) / g(x) when g(x) ≠0

(h/g)(4) = h(4) / g(4) = 59 / 14 because:

h(4) = 4(4)^2 - 5 ----> h(4) = 64 -5 =59

g(4) = 5(4) -6 -------> g(4) = 20 -6 =14

I hope it is useful,

Minoo