algebra The length of a new rectangular playing field is 9 yards longer than double the width. If the perimeter of the rectangular playing field is 330 ​yards, what are its​ dimensions?

Question

The length of a new rectangular playing field is

99

yards longer than

doubledouble

the width. If the perimeter of the rectangular playing field is

330330

​yards, what are its​ dimensions?

Answer 1

Hello, Stormie! I am more than happy to help you with this problem. If the length is 9 yards longer than double the width, then the length is 2w + 9. For a rectangle, there are 2 equal widths and 2 equal lengths. The sum of a rectangle is length + length + width + width, or (2w + 9) + (2w + 9) + w + w respectively, which is 6w + 18. Subsequently,

6w + 18 = 330

1. 18 -18

6w = 312

6 6

w = 52 yards, which is the width.

l = 2(52) + 9 = 113 yards, which is the length.