
Patrick B. answered 02/13/20
Math and computer tutor/teacher
A=1 b=-1 C=-1
b^2 - 4ac = (-1)^2 - 4(1)(-1) = 1 - 4(-1) = 1 + 4 = 5
x = (-(-1) + sqrt(5) ) / (2*1)
= (1 +or- sqrt(5))/2
check:
Let x = (1 +sqrt(5))/2 <--- the positive branch solution
Then x^2 = (1 + sqrt(5))^2/4 =
(1 + 2*sqrt(5) + 5)/4 =
(2 * sqrt(5) + 6)/4 =
(sqrt(5) + 3)/2
x^2 - x - 1 = (sqrt(5)+3)/2 - (1 + sqrt(5))/2 - 1
= 2/2 - 1 <--- there is negative sign in between so sqrt(5) cancels
= 1-1
= 0
therefore the solutions, appearing in bold above, are correct...