Formula for volume of a sphere = (4/3)∏r3
Remember that your teacher may want you to have these formulas memorized for your test unless you are given a formula sheet!
So to find the volume, you need r (radius). How do you get the radius from the info in the problem? Remember that the radius of a sphere is half the diameter, just like with a circle.
r = d/2 = 27/2
Extra information just in case you didn't understand that part: A sphere is basically a bunch of circles going from small to big to small diameters stacked and squished together. Think about how if you cut a sphere or a ball at its widest part (the middle), you would see a circle when you look at your cut. The diameter of a sphere runs across the widest part of the sphere (the middle).
Back to the problem: plug your value for r into the volume equation.
V = (4/3)∏r3
V = (4/3)∏(27/2)3
Then you simplify from here. Make sure you know whether your teacher wants a numerical answer with the pi calculated out - you could only do this if you are allowed a calculator.
If you aren't allowed a calculator, your teacher probably wants you to leave ∏ and the fraction in the equation (in its simplest form).
Here is the no-calculator way (except it would be nice to have a calculator for the cubed fraction so I hope you have a calculator lol). Otherwise, just carefully plug this equation into your calculator, following order of operations!
V = (4/3)∏(27/2)3
V = (4/3)∏ (19683 / 8) -> going to multiply these fractions and simplify. It would help to cross cancel.
V = ∏(6561 / 2) = 10305.995
Hope that makes sense!