
Patrick B. answered 02/03/20
Math and computer tutor/teacher
w = L + 4
Area = L * W = L"(L+4)
60 = l^2 + 4l
0 = L^2 + 4L - 60
0 = ( L + 10 )( L - 6 )
L+10 = 0 results in negative measures
L - 6 =0 --> L = 6
rectangle 6 by 10
Frances H.
asked 02/01/20The width of a rectangle is 4 units more than the length. If the area is 60 square units, then find the dimensions of the rectangle
Patrick B. answered 02/03/20
Math and computer tutor/teacher
w = L + 4
Area = L * W = L"(L+4)
60 = l^2 + 4l
0 = L^2 + 4L - 60
0 = ( L + 10 )( L - 6 )
L+10 = 0 results in negative measures
L - 6 =0 --> L = 6
rectangle 6 by 10
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