The length of a rectangle is 2 yd longer than its width. If the perimeter of the rectangle is 64 yd, find its length and width.

Answer 1

Hi there! I'd love to help you out.

We are dealing with a rectangle and we know its perimeter. The formula for a rectangle's perimeter is:

2W + 2L where W is our width and L is our length.

Now, we know that the length (L) of our rectangle is 2 yards longer than our width (W). In other words, if we add 2 to our W we get our length:

L = 2 + W

We can substitute this in for our perimeter equation and solve:

2W + 2( 2 + W) = 64

2W + 4 + 2W = 64

4W + 4 = 64

-4 -4

4W = 60

/4 /4

W = 15

So our width is 15 yards. Adding 2 yards to this we find our length is 17 yards.

I hope this explanation was thorough and answered all of your questions. If you have any additional equations please don't hesitate to comment or reach out! Learn on! :)