A possible rational root is 3 (it divides 15)
Dividing out (x-3) gives x2 +4x + 5 which has no real roots (i.e. 3 is a root and there are 2 complex roots.)
I do not understand what is being required in the 2nd part of the problem.
Alyssa N.
asked 01/30/20Find the roots
x^3 + x^2 = 7x + 15
then
given the zeros, write a polynomial function of least degree with integral coefficients
-3 (multiplicity of 2), root 5
A possible rational root is 3 (it divides 15)
Dividing out (x-3) gives x2 +4x + 5 which has no real roots (i.e. 3 is a root and there are 2 complex roots.)
I do not understand what is being required in the 2nd part of the problem.
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