Writing functions describing relationship of the given variables

Question

H varies directly with the square of d and when d=6, h=216

Answer 1

Hi there! I'd love to help you out with this!

When dealing with direct variation, we are multiplying by a constant and have the following equation:

y = xk where "k" is your constant

In this case, h varies with the square of d so we get:

h = d²k

Now we can plug in the values of h and d to find our coefficient:

216 = (6)²k

216 = 36k

/ 36 /36

6 = k

Now we have found our constant and can plug it into the direct variation equation:

h = 6d²

I hope this explanation was thorough and answered all of your questions. If you have any additional questions please don't hesitate to reach out! Learn on! :)