You need to evaluate this function when x is -1/3.
-2x^2 + x - 5 =
-2 * (-1/3)^2 + (-1/3) - 5 =
-2 * 1/9 + (-1/3) - 5 =
-2/9 + (-1/3) - 5 =
-2/9 + (-3/9) -5 =
-5/9 -5 = -5 5/9
The final solution is -5 and 5/9 (or -50/9) .
Yvette R.
asked 01/26/20f(x)=-2x^2+x-5 FIND: f(-1/3=
You need to evaluate this function when x is -1/3.
-2x^2 + x - 5 =
-2 * (-1/3)^2 + (-1/3) - 5 =
-2 * 1/9 + (-1/3) - 5 =
-2/9 + (-1/3) - 5 =
-2/9 + (-3/9) -5 =
-5/9 -5 = -5 5/9
The final solution is -5 and 5/9 (or -50/9) .
Nicholas B. answered 01/26/20
BS Electrical Engineering, Autodesk Certified User: Inventor
Solving for f(-1/3):
f(-1/3) = -2(-1/3)2 + (-1/3) - 5
Plug in -1/3 for all x's in the equation
f(-1/3) = -2(1/9) - 1/3 - 15/3
Solve the exponential and break 5 down into a fraction (it helps later)
f(-1/3) = -2/9 - 16/3
Finish multiplication and combine like terms
f(-1/3) = -2/9 - 48/9
Use a common denominator of 9 to finish simplifying
f(-1/3) = -50/9
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