Solving equation (algebra）

Question

How to solve this two equation?

Solve for B,

B log₂(1+B)=100;

Solve for n

40/(64^1.5n)=0.5/(12.8^n)+2/(0.8^64)^n

Answer 1

log_2(1+B)^B = 100

(1+B)^B = 2^100

1+B = (2^(100/B))

0 = (2^(100/B))-B-1 = f(B) is a function of B

must be solved numerically using newton's method, bisection method, and / or examining the graph.

The solution is close to -1