System of equations

Question

(X-3)^2+(y+2)=16

2x+2y=10

Answer 1

From eq 2, y = 5 - x, so we get (x - 3)² + 7 - x = 16, and x² - 7x + 16 = 16.

Then, x² - 7x = 0, and x = 0 and x = 7. When x = 0, y = 5. When x = 7, y = -2.

Speculation---maybe, given the form of eq 1, the intended problem had (y + 2)² with exponent 2 instead of blank.

Then we have (x - 3)² + (7 - x)² = 16.

Combining terms gives 2x² - 20x + 58 = 16, and therefore x² - 10x + 21 = 0. This will have roots of x = 3 (with y = 2) and x = 7 (with y = -2).

Answer 2

What is the assignment?? If you are supposed to solve for x and y, then you can use the 2nd equation to get an expression for either x or y and then substitute into the 1st equation