p(x) = x2 + 5x - 6

Question

1. Where p(x) intersects the y-axis.  
2. Where p(x) intersects the x-axis. 

Answer 1

Hi Martin R.,

p(x) intersects the y-axis when x = 0, (p(x) = y):

p(x) = (0)² + 5(0) - 6 = -6

p(x) intersects the x-axis when p(x) = 0

0 = x² +5x -6

0 = (x + 6)(x - 1)

x = -6 and x = 1

I hope this helps, Joe