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Question

If the equation 3(5)^2x=k is solved for x in terms of k, the result is

1) x=1/3log₂(k/5)

2)x=1/2log₅(k-3)

3)x=2log₅(3/k)

4)x=1/2log₅(k/3)

Answer 1

5^(2x) = k/3

takes log_5 of both sides:

2x = log_5(k/3)

x = (1/2) log_5(k/3)

= (1/2) [ log_5(k) - log_5(3) ]

option #4