What is the 20th term of the arithmetic sequence: [4, 16, 28, ...]

Answer 1

Use the formula: a_n = a₁ + (n-1)d where n is the term you are trying to find, d is the common difference, and a₁ is the first term in the sequence.

If you substitute in your values, you get:

a₂₀ = 4 + (20-1)12

a₂₀ = 4 + 19(12)

a₂₀ = 4 + 228

a₂₀ = 232

Answer 2

use the formula a_n=a₁+(n-1)d where n=term 20, a₁=first term, d=common difference which is 12

a₂₀=4+(20-1)12

a₂₀=4+(19)(12)

a₂₀=4+228

a₂₀=232