Hey, Im currently doing the IXL exercise "Simplify radical expressions with variables". The question is ∛-(x+2)^8

Answer 1

³√(-(x+2)⁸) = ³√(-1) ³√(x+2)⁸ = -³√(x+2)^{6 3}√(x+2)² = -(x+2)^{2 3}√(x+2)²

Answer 2

Multiply the powers..-(x+2)^(8/3); that is 1/3*8.

Answer 3

Set u = (x + 2)

³√-u⁸

³√-(u²)⁴

³√-(u²)³(u²)

u^{2 3}√-u²

(x + 2)^{2 3}√-(x + 2)²

Answer 4

Think of the cube root as taking the expression under the radical to the one-third power. Then multiply the exponents:

-(x+2) to the eight-thirds power, or -(x+2)^(8/3)