This is what is known as a "combination" (versus "permutation") since the order in which the 3 people are selected does not matter. If each job were unique, then you would use a permutation (which is always a larger number). The formula for combinations is sample space (factorial) divided by the product of the number being selected (factorial) and the difference of the two (factorial); i.e, 12!/(3!*9!) =220
Grace G.
asked 01/02/20binomial distribution
In how many ways can a member of a hiring committee select 3 of 12 job applicants for further consideration?
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Barry M. answered 01/02/20
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12!/(9!3!)
= 12 X 11 X 10 / 6
= 220
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