Arturo O. answered 12/21/19
Experienced Physics Teacher for Physics Tutoring
From the wording of the problem, it is not clear if the multiplicity of 2 applies to both zeros or just to the zero of 5. I will assume the latter. (In any case, you will see the method.)
Zeros: -3; and 5 with multiplicity of 2
f(x) = A(x + 3)(x - 5)2
where A is real and A ≠ 0. Note the multiplicity is the exponent in (x - z)n, where z is a zero and n is the multiplicity of z. Now expand f(x) into standard form and finish from here.