Always start with GCF factoring. The GCF of 54x3y - 16y4 is 2y so we have:
54x3y - 16y4
2y(27x3 - 8y3) which is a difference of cubes where a = 3x and b is 2y
2y(3x - 2y)(9x2 + 6xy + 4y4)
Hope this helps!

Grady N.
asked 12/19/19I have a test tomorrow and i am studying but i am stuck on this problem any help would be greatly appreciated. The problem is to factor 54x^3y - 16y^4.
Always start with GCF factoring. The GCF of 54x3y - 16y4 is 2y so we have:
54x3y - 16y4
2y(27x3 - 8y3) which is a difference of cubes where a = 3x and b is 2y
2y(3x - 2y)(9x2 + 6xy + 4y4)
Hope this helps!
Mark M. answered 12/19/19
Retired college math professor. Extensive tutoring experience.
Recall: A3 - B3 = (A - B)(A2 + AB + B2)
54x3y - 16y4 = 2y(27x3 - 8y3) = 2y[(3x)3 - (2y)3] = 2y(3x - 2y)[(3x)2 + (3x)(2y) + (2y)2] =
2y(3x - 2y)(9x2 + 6xy + 4y2)
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Kerri P.
12/19/19