college algebra

Question

The sum of three numbers is 108

. The second number is 4

 times the third. The first number is 6

 more than the third. What are the numbers?

Answer 1

Hello Teenea The way I will solve this is like doing a Substitution Method.:

x + y +z =108 (Sum of 3 numbers)

4z ( z is the 3rd number in the "y" position or 4 times z)

z +6 x is 6 MORE than the 3rd, where z is the 3rd in the X position)

_____________________________ NOTICE THE Z's in COMMON. Lets solve for "Z".

x + y + z =108

(z+6) +4z + z =108 (ADD THE Z's )

z+ 6 + 5z =108

-6 -6 (Subtract 6)

__________________________

z + 5z =102

6z =102

__________________

6 6 (DIVIDE BOTH SIDES BY 6)

Z= 17

Y=4z Y =4(17) =68 (We have y=68 Z= 17)

X= Z_+ 6 Z= 17 X= (17+6)=23 X + Y + Z =108

( 23 + 68 + 17 ) = 108

(91 + 17) = 108

108 =108

Hope this helps !