Jeff K. answered 06/08/20
Together, we build an iron base of understanding
Hi Lexi:
This is a common type of compound interest problem.
The compound interest formula: A = P(1 + i%/100)n
where A = final amount, P = principal invested, i = int rate % per period, n = # of compounding periods
Let the amount invested be P => Amount = 2P since the investment doubles
Let the required time be n years.
∴ 2P = P (1 + 13%/12)12n [interest is compounded monthly @ 13%/12 per month for 12n months
2 = (1 + 0.01083333)12n [dividing both sides by P
2 = 1.0108333312n
Since the unknown is an exponent ( a power), we take logs on both sides
ln 2 = 12n x ln 1.01083333
12n = ln 2 / ln 1.010833333
n = 5.36 years
The 0.36 years are 0.36 x 12 months = 4.3 months
So, it takes 5 years and 5 months to double (rounding up to the nearest month)