Let x = amount of 70% antifreeze
The 130-x = the amount of 95% antifreeze
Then,
{ 70x + 95(130-x) }/(x + 130 + x) = 75 or 70x + 12,350 - 95x = 9,750
or 25x = 2,600
x = 104 gallons of 70% antifreeze
the 130-x = 26 gallons of 95% antifreeze
Nikki A.
asked 12/02/19A chemical company makes two brands of antifreeze. The first brand is 70%
pure antifreeze, and the second brand is 95%
pure antifreeze. In order to obtain 130
gallons of a mixture that contains 75%
pure antifreeze, how many gallons of each brand of antifreeze must be used?
Let x = amount of 70% antifreeze
The 130-x = the amount of 95% antifreeze
Then,
{ 70x + 95(130-x) }/(x + 130 + x) = 75 or 70x + 12,350 - 95x = 9,750
or 25x = 2,600
x = 104 gallons of 70% antifreeze
the 130-x = 26 gallons of 95% antifreeze
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