Denise G. answered 11/18/19
Algebra, College Algebra, Prealgebra, Precalculus, GED, ASVAB Tutor
Let x=width
Let x-8=length
Formula: Area = length x width
Plugging values in:
240 = x(x-8) Distribute
240 = x2-8x Subtract 240 from both sides
0=x2-8x-240 Factor
0=(x-20)(x+8) Set factors = 0 and solve
x-20=0 Add 20 to both sides
x=20
x+8=0 Subtract 8 from both sides
x=-8 (This cannot be a valid solution, width cannot be negative)
length = x-8 = 20-8 = 12
The dimensions would be 20 yd x 12 yd