ellipses conic sections

Question

find the center of the ellipse

4x²+y²-48x+4y+48=0

Answer 1

4x^2 +y^2 - 48x + 4y + 48 = 0

4x^2 - 48x + y^2 + 4y = -48

4(x^2 - 12x ) + (y^2 + 4y ) = -48

4(x^2 - 12x + 6^2) + (y^2 + 4y + 2^2) = -48 + 4(6^2) + 2^2

4(x - 6)^2 + (y + 2)^2 = -48 + 144 + 4 = 100

Center at (6, -2)